a.
\[m_\mathrm{Cu} = M_\mathrm{Cu} \cdot n_\mathrm{Cu} = 63,55\frac {\mathrm{g}}{\mathrm{mol}} \cdot 0,25\mathrm{mol} = 15,8875\mathrm{g} ≈ 16\mathrm{g}\]
Svar: \(m_\mathrm{Cu} = 16\mathrm{g}\)
b.
\[m_\mathrm{H_2O} = M_\mathrm{H_2O} \cdot n_\mathrm{H_2O} = (1,008 \cdot 2 + 16,00)\mathrm{g/mol} \cdot 1,5\mathrm{mol} = 27,024\mathrm{g} ≈ 27\mathrm{g}\]
Svar: \(m_\mathrm{H_2O} = 27\mathrm{g}\)
c.
\[m_\mathrm{HCl} = M_\mathrm{HCl} \cdot n_\mathrm{HCl} = (1,008 + 35,45)\mathrm{g/mol} \cdot 2,25\mathrm{mol} = 82,0305\mathrm{g} ≈ 82\mathrm{g}\]
Svar: \(m_\mathrm{H_2O} = 27\mathrm{g}\)
d.
\[\begin{aligned} m_\mathrm{CH_3OH} &= M_\mathrm{CH_3OH} \cdot n_\mathrm{CH_3OH} = (12,01 + 1,008 \cdot 4 + 16,00)\mathrm{g/mol} \cdot 9,27\mathrm{mol} = \\ &= 297,02934\mathrm{g} ≈ 297\mathrm{g} \end{aligned}\]
Svar: \(m_\mathrm{CH_3OH} = 297\mathrm{g}\)
e.
\[\begin{aligned}m_\mathrm{CuSO_4} &= M_\mathrm{CuSO_4} \cdot n_\mathrm{CuSO_4} = (63,55 + 32,07 + 16,00 \cdot 4)\mathrm{g/mol} \cdot 5,2\mathrm{mol} = \\ &= 830,024\mathrm{g} ≈ 0,83\mathrm{kg}\end{aligned}\]
Svar: \(m_\mathrm{CuSO_4} = 0,83\mathrm{kg}\)
