a.
CoCl2 · 6H2O(s) \( \overset{\Delta}{\rightarrow}\) CoCl2(s) + 6H2O(g)
b.
\(n_\mathrm{CoCl_2 \cdot 6H_2O}:n_\mathrm{H_2O} = 1:6\) ⇒ Det bildas 6 mol.
c.
| CoCl2 · 6H2O(s) | → CoCl2(s) | + 6H2O(g) | |
| \[m\] | ①\[1,0\mathrm{g}\] | ④\[0,45\mathrm{g}\] | |
| \[n\] | ②\[0,00420299\mathrm{mol}\] | ③\[0,02521792\mathrm{mol}\] |
① \(m_\mathrm{CoCl_2 \cdot 6H_2O} = 1,0\mathrm{g}\)
②
\(\begin{aligned}n_\mathrm{CoCl_2 \cdot 6H_2O} &= \frac {m_\mathrm{CoCl_2 \cdot 6H_2O}}{M_\mathrm{CoCl_2 \cdot 6H_2O}} = \frac {1,0\mathrm{g}}{(58,93+25,45 \cdot 2 + 6 \cdot (1,008 \cdot 2 + 16,00))\mathrm{g/mol}} = \\ &= 0,00420299\mathrm{mol}\end{aligned}\)
③
\(n_\mathrm{CoCl_2 \cdot 6H_2O}:n_\mathrm{H_2O} = 1:6 \\ n_\mathrm{H_2O} = 6n_\mathrm{CoCl_2 \cdot 6H_2O} = 6 \cdot 0,00420299\mathrm{mol} = 0,02521792\mathrm{mol}\)
④
\(\begin{aligned}m_\mathrm{H_2O} &= M_\mathrm{H_2O} \cdot n_\mathrm{H_2O} = (1,008 \cdot 2 + 16,00)\mathrm{g/mol} \cdot 0,02521792\mathrm{mol} = \\ &= 0,45432614\mathrm{g} ≈ 0,45\mathrm{g}\end{aligned}\)
