Svavelsyran neutraliseras:
H2SO4(aq) + 2NaOH(aq) → 2H2O + Na2SO4(aq)
\[\begin{aligned} n_\mathrm{H_2SO_4} &= c_\mathrm{H_2SO_4} \cdot V_\mathrm{H_2SO_4} = 0,111\frac {\mathrm{mol}}{\mathrm{dm^3}} \cdot 0,0150\mathrm{dm^3} = 0,001665\mathrm{mol} \end{aligned}\]
\[n_\mathrm{H_2SO_4}:n_\mathrm{NaOH} = 1:2 \\ n_\mathrm{NaOH} = 2n_\mathrm{H_2SO_4} = 2\cdot 0,001665\mathrm{mol} = 0,00333\mathrm{mol}\]
\[V_\mathrm{NaOH} = \frac {n_\mathrm{NaOH}}{c_\mathrm{NaOH}} = \frac {0,00333\mathrm{mol}}{0,150\frac {\mathrm{mol}}{\mathrm{dm^3}}} = 0,0222\mathrm{dm^3} = 22,2\mathrm{ml}\]
